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小4_算数科_字幕_xを使った式について考える①
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小4_算数科_字幕_xを使った式について考える②
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小4_算数科_xを使った式について考える②
小4_算数科_xを使った式について考える①
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小4_算数科_xを使った式について考える④
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lim _x → a(x+2)^5 / 3-(a+2)^5 / 3/x-a= (1) 5/3(a+2)^2 / 3 (2) 5/3 ...
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Let α, β∈ℝ be such that lim _x → 0x^2sin (β x)/α x-sin x=1 ...
lim _x →∞ 2(√(25 x^2+x)-5 x) is equal to : (a) lim _x → 02 x ...
lim _x → 0x^2cos x/1-cos x is (A) 2 (B) 3/2 (C) -3/2 (D) 1 lim _x ...
Find lim _x → 5 f(x),here f(x)=|x|-5 L H L=R H L lim _x → 5^- f(x ...
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Instagram video by @pola._x • Feb 20, 2023 at 6:22 AM
Let a=lim _x → 1(x/ln x-1/x ln x) ; b=lim _x → 0x^3-16 x/4 x+x ...
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lim _x → 1(1-x) tanπ x/2=… (1978,2 M)
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Evaluate the following limits, if exists P_W lim _x → 0ln (1+3 x ...
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Let F(x)=∫_x^x^2+π/6 2 cos ^2 t d t for all x ∈ R and f:[0, 1/2 ...
lim _x →π/6cosec^2 x-4/cosec x-2 (a-b)(a+b)=a^2-b^2 lim _x ...
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lim _x → 3x^-5-1/243/x-3= (a) -5/729 (b) -5/243 (c) 5/81 (d) 5/729
lim _x → 0sin(x^2)/ln(cos(2 x^2-x)) is equal to(1) 2 (2) -2 (3) 1 ...
Evaluate: lim _x → 0√(1+x^3)-√(1-x^3)/x^2 Given lim _x → 0 ...
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lim _x →π / 4cosec x- x/ x-tan x (A) (C) [ √() 2 (B) 1 / √() 2; 1 / 2
Evaluate: lim _x → 0sin 3 x/sin 7 x lim _x → 0sin 3 x/sin 7 x=0 ...
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小4_算数科_字幕_xを使った式について考える④

  


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